Answer:
Let L be the length of the rectangle and w be the width of the rectangle.
"The lenght of a rectangle is one less than twice the width" means L=2W-1
Using perimeter formula of a rectangle which is P=2(L+W) you have:
P=2(L+W)
130=2(2W-1+W)
Solve equation above to find W
130=2(3W-1)
130=6W-2
130+2=6W
132=6W
W=22
From here you find L=2W-1=2x22-1=43
Only thing left is to find area A=LxW
