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A compound is found to contain 59.94 % carbon , 13.44 % hydrogen , and 26.62 % oxygen by mass.

To answer the question, enter the elements in the order presented above.

QUESTION 1:
The empirical formula for this compound is

Respuesta :

Empirical formula is C5H13O2

For C, 59.94/12.01= 4.99 =5

For H, 13.44/1.0079=13.33= 13

For O, 26.62/15.999=1.66=2