Answer:
[tex]75.04gC_6H_{12}O_6[/tex]
Explanation:
Hello!
In this case, since one mol of any atom is related via the Avogadro's number and each mol of glucose has 6 moles of atoms of oxygen, it is possible to obtain the moles of glucose as shown below:
[tex]1.505x10^{24}atomsO*\frac{1molO}{6.022x10^{23}atoms O}*\frac{1molC_6H_{12}O_6}{6molO}\\\\=0.4165 mol C_6H_{12}O_6[/tex]
Thus, since the molar mass of glucose is 180.15 g/mol, the mass turns out to be:
[tex]0.4165mol*\frac{180.15g}{1mol} \\\\=75.04gC_6H_{12}O_6[/tex]
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