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An envelope measures 9 inches by 4 inches. A pencil is placed at a diagonal. What is the maximum possible length of the pencil? If necessary round to the nearest tenth

Respuesta :

Answer:

d = 9.84 m

Step-by-step explanation:

The dimensions of an envelope are 9 inches by 4 inches.

We need to find the maximum possible length of the pencil.

Let it be d. It can be calculated using Pythagoras theorem such that,

[tex]d=\sqrt{9^2+4^2} \\\\d=9.84\ m[/tex]

So, the maximum possible length of the pencil is 9.84 m./

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