A system of equations consists of y = x3 + 5x + 1 and y = x. The equations are equal at approximately x = -0.25, -0.5, 0.5, 0.25

y = x^3 + 5x + 1
y = x

When they are equal
x^3 + 5x + 1 = x
x^3 + 4x + 1 = 0
x(x^2 + 4) = -1

-0.25((-0.25)^2 + 4) = -0.25(0.0625 + 4) = -1.02

Therefore, the equation is equal at approximately x = -0.25

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calculista calculista · Answer 2 · 2019-01-03T03:00:08+01:00

calculista calculista

03-01-2019

Answer:

[tex]x=-0.25[/tex]

Step-by-step explanation:

we have

[tex]y=x^{3}+5x+1[/tex] -----> equation A

[tex]y=x[/tex] -----> equation B

Using a graphing tool-----> to resolve the system of equations

Remember that the solution of the system of equations is equal to the intersection point both graphs

see the attached figure

the solution is [tex]x=-0.25[/tex]

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