Answer:
the answer is B (2,1)
Step-by-step explanation:
Given the simultaneous equation
[tex]2x+3y=7 .....1\\x+y=3 ..........2\\[/tex]
Using substitution method
from equation 2 :
[tex]x=3-y ....3[/tex]
Substitute equation 3 into 1:
[tex]2(3-y)+3y=7[/tex]
Open the bracket
[tex]2(3)-2y+3y=7\\6-2y+3y=7\\6+y=7\\y=7-6\\y=1[/tex]
Substitute y=1 into x=3-y
[tex]x=3-1\\x=2[/tex]
Hence the solution to the equation is (2,1)
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