Given:
A line passes through (-1, 3) and (5,3).
To find:
The equation of the line.
Solution:
The line passes through (-1, 3) and (5,3). So, the equation of the line is
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-3=\dfrac{3-3}{5-(-1)}(x-(-1))[/tex]
[tex]y-3=\dfrac{0}{5+1}(x+1)[/tex]
[tex]y-3=0[/tex]
Adding 3 on both sides, we get
[tex]y-3+3=0+3[/tex]
[tex]y=3[/tex]
Therefore, the equation of the line is [tex]y=3[/tex].
