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contestada

A poisoned pill contains 0.00048 moles of KCN. How many molecules are in this sample?

Respuesta :

Answer:

[tex]2.89 \times {10}^{20} \: \: molecules[/tex]

Explanation:

The number of molecules of KCN can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.00048 × 6.02 × 10²³

We have the final answer as

[tex]2.89 \times {10}^{20} \: \: \: molecules[/tex]

Hope this helps you