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Choose the SYSTEMS option.
3) If you are given the following two objects and apply 100 N of force to each
which of the two would you expect to stretch further?
one.
Object 1: k = 100 N/m
Object 2: k = 200 N/m

Respuesta :

Answer:

Object 1.

Explanation:

Given that,

Force applied = 100 N

The spring constant of object 1 = 100 N/m

The spring constant of object 2 = 200 N/m

Using Hooke's law, we find the force applied on the object to stretch.

For object 1,

F₁ = k₁x₁

[tex]x_1=\dfrac{F_1}{k_1}\\\\x_1=\dfrac{100}{100}\\\\=1\ m[/tex]

For object 2,

F₂ = k₂x₂

[tex]x_2=\dfrac{F_2}{k_2}\\\\x_2=\dfrac{100}{200}\\=0.5\ m[/tex]

Object 1 stretches 1 m and object 2 stretches 0.5 m. Hence, object 1 stretches furthur.

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