Answer:
39.2 %
Explanation:
The following data were obtained from the question:
Mass of sample = 24 g
Mass of Cl = 14.6 g
Mass of B = 9.4 g
Percentage composition of boron =?
The percentage composition (by mass) of boron in the sample can be obtained as illustrated below:
Percentage composition of boron = mass of B /mass of sample × 100
Percentage composition of boron = 9.4/24 × 100
Percentage composition of boron = 39.2 %
Therefore, the percentage composition (by mass) of boron in the sample is 39.2 %
The percent composition of boron in this sample is 39.17 %.
The mass of chlorine = 14.60 g
The mass of Boron = 9.400g
Mass of the sample = 24.00 g
The percentage composition of boron can be calculated below:
% composition of Boron = 9.4 / 24 × 100
% composition of Boron = 940 / 24
% composition of Boron = 39.1666666667
% composition of Boron ≈ 39. 17%
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