Answer:
The probability is [tex]P( p < 435.82 ) = 0.54094[/tex]
Step-by-step explanation:
From the question we are told that
The population proportion is p = 54% = 0.54
The sample size is n = 808
Generally the distribution of the population with college degree follows a binomial distribution
i.e
[tex]X \~ \ \ \ B(n , p)[/tex]
Generally the mean is mathematically represented as
[tex]\mu = n * p[/tex]
=> [tex]\mu = 808 * 0.52[/tex]
=> [tex]\mu = 420.16[/tex]
Generally the standard deviation is mathematically represented as
[tex]\sigma = \sqrt{np(1- p )}[/tex]
=> [tex]\sigma = \sqrt{808 * 0.52(1- 0.52 )}[/tex]
=> [tex]\sigma = 14.2[/tex]
Generally 54% of the population proportion is
[tex]\^ p = 0.54 * 808[/tex]
=> [tex]\^ p = 436.32[/tex]
Generally by normal approximation of the binomial distribution the probability that the proportion of persons with a college degree will be less than 54% is mathematically evaluated as
[tex]P(p < \^ p ) = P(\frac{p - \mu }{\sigma } < \frac{\^ p - \mu }{\sigma } )[/tex]
[tex]\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )[/tex]
=> [tex]P(p < 436.32 ) = P( Z < \frac{436.32 - 420.16 }{14.20 } )[/tex]
applying continuity correction
[tex]P(p < (436.32-0.5) ) = P( Z < \frac{(436.32-0.5) - 420.16 }{14.20 } )[/tex]
=> [tex]P(p < (435.82 ) = P( Z < \frac{435.82 - 420.16 }{14.20 } )[/tex]
=> [tex]P(p < (435.82 ) = P( Z < 0.1028 )[/tex]
From the z table the area under the normal curve to the left corresponding to 0.1028 is
[tex]P( Z < 0.1028 ) = 0.54094[/tex]
=> [tex]P( p < 435.82 ) = 0.54094[/tex]
