Given:
Total number of tickets = 600
Cost of adult ticket = $6.00
Cost of student ticket = $4.00
Total sales = $2900.00
To find:
The number of tickets of each type.
Solution:
Let the number of adult tickets be x and number of student tickets be y.
According to the question,
[tex]x+y=600[/tex] ...(i)
[tex]6x+4y=2900[/tex] ...(ii)
Multiply equation (i) by 4 and subtract the result from (ii),
[tex]6x+4y-4(x+y)=2900-4\times 600[/tex]
[tex]6x+4y-4x-4y=2900-2400[/tex]
[tex]2x=500[/tex]
Divide both sides of 2.
[tex]x=250[/tex]
Put x=250 in (i).
[tex]250+y=600[/tex]
[tex]y=600-250[/tex]
[tex]y=350[/tex]
Therefore, number of adult tickets is 250 and number of student tickets is 350.
