Answer:
[tex]\mu=0.23[/tex]
Explanation:
Given that,
Mass of a flower pot = 3 kg
The force that is required to move the pot is 6.77 N
We need to find the coefficient of friction for the flower pot.
The force required to move an object in terms of coefficient of friction is given by :
[tex]F=\mu N[/tex]
N is normal force
[tex]F=\mu mg\\\\\mu=\dfrac{F}{mg}\\\\\mu=\dfrac{6.77}{3\times 9.8}\\\\\mu=0.23[/tex]
So, the coefficient of friction for the flower pot is 0.23.
