Respuesta :

  • Gram molecular mass of Cr2(SO4)3 = 392.6 g
  • No. of moles in 39.2 g of Cr2(SO4)3 = 39.2/392.6 = 0.1 mol  
  • 1 mol of Cr2(SO4)3 contains = 3 x 6.023 x 1023 sulphate ions
  • So, 0.1 mol of Cr2(SO4)3 will contain = 0.1 x 3 x 6.023 x 1023 = 1.8069 x 1023 sulphate ions

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