Answer:
γ = [tex]\lim_{n \to \infty}\sum_{k=1}^n (\frac{1}{k}-ln(n) )[/tex]
or
γ = -∞
Step-by-step explanation:
Let's solve what's inside the limit first.
We see that we need to take the sum of the entire thing. Since it is multivariable and we are given 1 variable, it stays the same.
Now we move on to the limit.
We replace n in the summative with infinity.
The natural log of infinity is infinity.
1 minus infinity would be negative infinity.
The sum of negative infinity of k = 1 is negative infinity.
So the limit as n approaches infinity would be negative infinity.
If we were to simplify this mathematically, it would just be the same equation.
