If 52500 J of heat is used to heat a 10200g block of metal and
the temperature of the metal increases by 11 2°C Calculate the
specific heat capacity of the metal.

Respuesta :

Answer:

45.95 Jkg^-1°C^-1

Explanation:

as specific heat capacity = heat energy / mass × delta

temperature

=52500/10.2×112

=45.95 Jkg^-1°C^-1