Answer:
The correct option is;
2. (750 - w)(13) = d (750 + w)(11) = d - 250
Step-by-step explanation:
The items with information given are;
The cruising speed of the planes = 750 km/h
The first plane flies against a constant headwind = w
The second plane flies against a constant tailwind in magnitude to the headwind
The time duration of flight of the first plane = 13 hours
The time duration of flight of the second plane = 11 hours
The distance flown by the second plane = The distance flown by the first plane - 250 km
When we take the headwind magnitude as, w and the distance flown by the first plane as d, we have;
Speed of flight of the first plane = 750 - w
Speed of flight of the second plane = 750 + w
Therefore, the distance flown by the first plane in 13 hours is given as follows;
(750 - w) × (13) = d
Then we have;
The distance flown by the second plane in 11 hours is (750 + w) × (11) = d.
The correct option is (750 - w)(13) = d, (750 + w)(11) = d - 250
