Help me with this...

i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
[tex]333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \: - x = 630 - 801 \\ or \: - x = - 171 \\ x = 171[/tex]
Hope this helps...
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