Answer:
44.76 miles
Step-by-step explanation:
The First Ship travels at 15 mph from A to C
Distance covered in 2 hours =15 X 2 =30 Miles
The Second Ship travels at 11 mph from A to B
Distance covered in 2 hours =11 X 2 =22 Miles
The path of the two ships forms a triangle ABC where:
AB=22 Miles
AC=30 miles
[tex]\angle A=13^\circ+90^\circ+15^\circ\\\angle A=118^\circ[/tex]
We want to determine the distance BC between the two ships.
Using Law of Cosines
[tex]a^2=b^2+c^2-2bc\cos A\\a^2=30^2+22^2-2*30*22\cos 118^\circ\\a^2=2003.7025\\a=\sqrt{2003.7025}\\a=44.76$ miles[/tex]
BC= 44.76 miles
After two hours, the two ships are 44.76 miles apart.
