Answer:
Area of the figure = 31.25π cm²
Perimeter of the figure = (12.5π + 10) cm
Step-by-step explanation:
Area of the given figure = Sum of area of the two semicircle + area of a quarter circle
Area of one quarter circle (CDE) = [tex]\frac{1}{4}(\pi r^{2})[/tex]
= [tex]\frac{1}{4}\pi (5)^2[/tex]
= 6.25π
Area of one semicircle = 2 × Area of one quarter circle
= 2(6.25π)
= 12.5π
Area of the given figure = 2×12.5π + 6.25π
= 25π + 6.25π
= 31.25π cm²
Perimeter of the figure = Perimeter of two semicircles + perimeter of one quarter circle + measure of radius DE + measure of radius AB
Perimeter of one semicircle = πr
= 5π cm
Perimeter of one quarter circle = 2.5π
Perimeter of the complete figure = 10π + 2.5π + 5 + 5
= (12.5π + 10) cm
