awcain03
contestada

A key code must contain 4 numerals. There are 10 numerals available. Using
these numerals, how many different key codes may be created?
O A. 180
O B. 210
O C. 3,060
O D. 5,040​

Respuesta :

ARay10

Answer:

B, 210

Step-by-step explanation:

[tex]\dbinom{10}{4} = \dfrac{10!}{6! \cdot 4!} = \dfrac{10 \cdot 9 \cdot 8 \cdot 7}{4 \cdot 3 \cdot 2 \cdot 1} = 5 \cdot 3 \cdot 7 \cdot 2 = 210[/tex]

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