Step-by-step explanation: The base of the power in the original equation becomes the base of the log. So we have [tex]^{log}3[/tex].
Next, the exponent in the original equation goes on the other side of the equation and finally, the result in the original equation goes inside the log.
So we have [tex]^{log} 3[/tex] [tex]9 = 2[/tex] which is 3² = 9 written in logarithmic form.
This can also be switched around to read [tex]2 = ^{log} 3 = 9[/tex].
So the first choice will be your answer.
My work is also show in the image attached,
I just didn't switch it.
