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the student records the concentration of the stock solution of H2O2 to be 0.950 M. The student proceeds to prepare the reaction solution as stated in Step 9: They add 10.0 mL of 0.10 M potassium iodide and 15.0 mL of distilled water to their flask. They then add 5.0 mL of the stock H2O2 solution and mix the solution to initiate the reaction. Calculate the molarity of I- in the initial reaction solution.

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Answer:

0.0400M of KI

Explanation:

Molarity is an unit of concentration defined as the ratio between moles of solute and liters of solution.

When you add 10.0 mL of 0.10M KI and 15.0mL, total volume is:

25.0mL = 0.025L of solution

And moles of KI are:

0.0100L × 0.10M = 0.00100 moles of KI

Thus, molarity is:

0.00100 moles / 0.025L = 0.0400M of KI

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