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If two opposite sides of a square are increased by 5 meters and the other sides are decreased by 2 meters, the area of the rectangle that is formed is 60 square meters find the original square

Respuesta :

Let the original length of the square be x cm.
(x+5) X (x-2) = 60
Or, x^2-2x+5x-10-60 = 0
Or, x^2+3x-70=0
Or, x^2+10x-7x-70=0
Or, x(x+10)-7(x+10)=0
Or, (x-7)(x+10)=0
Therefore, x=7 or x=-10 (rejected as the length cannot be negative)
Ans: Area of the square=l^2=7^2=49 square meters.

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