Answer:
[tex]\huge\boxed{B.\ x^2+(y-3)^2=16}[/tex]
Step-by-step explanation:
The equation of a circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
where
[tex](h,\ k)[/tex] - center
[tex]r[/tex] - radius
From the graph we have
center - (0, 3) → h = 0, k = 3
radius - r = 4
Substitute:
[tex](x-0)^2+(y-3)^2=4^2\\\\x^2+(y-3)^2=16[/tex]
