Mechano, the evil robot cat, has captured the mous
Mechano, the evil robot cat, has captured the mouse, Jerry (mJ = 0.500 kg), and is about to launch him out of a window using his robotic sling shot.

Part A: You can see that the sling shot has two elastic bands that hold the pouch, which is wrapped around Jerry. Treat each of the bands like a Hooke\'s Law spring, with a spring constant of k = 1800 N/m.The rest length of each \"spring\" is L0 = 0.0550 m. At the time of the launch, the \"springs\" have a length of Lf = 0.100 m.

Part B: What is Jerry\'s speed (vJ) when he leaves the sling shot?

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kollybaba55 kollybaba55 · Answer 1 · 2020-04-13T03:01:44+02:00

Answer:

a) potential energy in the spring = 1.8225 J

b) Jerry's speed = 2.744 m/s

Explanation:

a) The spring constant, k = 1800 N/m

The rest length of the spring, [tex]L_{0} = 0.0550 m[/tex]

The launch length, [tex]L_{f} = 0.100 m[/tex]

The potential energy of each spring is , [tex]PE = 0.5 k(\triangle x)^{2}[/tex]

[tex]\triangle x = 0.1 - 0.055 = 0.045 m[/tex]

[tex]PE = 0.5 * 1800* 0.045^{2}[/tex]

PE = 1.8225 J

b) To get Jerry's speed, use the law of energy conservation

PE energy in the string = KE of the robot

[tex]KE = 0.5mv^{2}[/tex]

PE in the spring = 1.8225 J

[tex]1.8825 = 0.5 mv^{2} \\1.8825 = 0.5 * 0.5 v^{2} \\1.8825 = 0.25 v^{2} \\ v^{2} = 1.8825/0.25\\v^{2} = 7.53[/tex]

v = 2.744 m/s