Answer: The electronic configuration of the atom that represents excited state is P: [tex]1s^22s^22p^63s^23p^24s^1[/tex]
Explanation:
There are 2 states classified under energy levels:
For the given options:
The atomic number of sodium element is 11. The ground state electronic configuration of this element is [tex]1s^22s^22p^63s^1[/tex]
The atomic number of neon element is 10. The ground state electronic configuration of this element is [tex]1s^22s^22p^6[/tex]
The atomic number of nitrogen element is 7. The ground state electronic configuration of this element is [tex]1s^22s^22p^3[/tex]
The atomic number of phosphorus element is 15. The ground state electronic configuration of this element is [tex]1s^22s^22p^63s^23p^3[/tex]
One electron from the valence shell jumps into outer shell and the excited state electronic configuration becomes [tex]1s^22s^22p^63s^23p^24s^1[/tex]
The atomic number of helium element is 2. The ground state electronic configuration of this element is [tex]1s^2[/tex]
Hence, the electronic configuration of the atom that represents excited state is P: [tex]1s^22s^22p^63s^23p^24s^1[/tex]