Answer:
The maximum speed the stone can attain without breaking the string is 7.416 m/s
Explanation:
Given;
mass of the stone, m = 0.600 kg
length of string, L = 0.600 m
maximum tension on the string, T = 55.0 N
Total force acting on the stone in horizontal direction is given as;
∑[tex]F_x =T =\frac{mv^2}{r}[/tex]
This force corresponds to maximum tension on the string;
[tex]T_{max} =m\frac{v_{max}^2}{r}[/tex]
where;
m is the mass of the stone
[tex]v_{max}[/tex] is the maximum speed the stone can attain without breaking the string, which corresponds to maximum tension on the string.
r is radius of the circular path of the string
[tex]v_{max}^2 = \frac{Tr}{m} \\\\v_{max} = \sqrt{\frac{Tr}{m}} \\\\v_{max} = \sqrt{\frac{55*0.6}{0.6}} = 7.416 \ m/s[/tex]
The maximum speed the stone can attain without breaking the string is 7.416 m/s
