Respuesta :

dalendrk
[tex]2x-6y=1\ \ \ |add\ 6y\ to\ both\ sides\\\\2x=6y+1\ \ \ |divide\ both\ sides\ by\ 2\\\\x=3y+0.5\\\\\boxed{f(x)=\frac{1}{3}x-\frac{1}{6}\to f^{-1}(x)=3x+0.5}[/tex]