2C₃H₆ + 9O₂ ------> 6CO₂ + 6H₂O
moles of C₃H₆ = [tex] \frac{MASS}{Molar Mass} [/tex]
= [tex] \frac{41.8 g}{(12 * 3) + (6)} [/tex]
= 0.995 mol
ratio of C₃H₆ : O₂
2 : 9
∴ mol of O₂ = [tex] \frac{0.995 mol * 9}{2} [/tex]
= 4.479 mol
Mass of O₂ = (Molar Mass) * (Mole)
= (16 * 2) g/mol * (4.479)mol
= 143.31 g
