Answer:
Volumetric flow rate = [tex]v=0.1232 m^3 /s[/tex]
Step-by-step explanation:
The volumetric flow rate v= area x velocity
from the given data we will find out area and velocity first.
Area = A = (π /4) d^2
Diameter = d = 15 cm = 0.15 m
Area = A = [tex](3.14/4) * 0.15^2\\Area = A =0.0176 m^2[/tex]
The velocity = V = [tex]\sqrt{2gH}[/tex]
height of wine in the tank = H = 2.5 m
[tex]Velocity = V = \sqrt{2*9.8*2.5}\\Velocity = V = 7 m/s\\[/tex]
Now calculating the volumetric flow rate
v = A x V
v = 0.0176 x 7
[tex]v=0.1232 m^3 /s[/tex]
The volumetric flow rate into the tank if the wine level remains constant will be 0.1232 m³/s.
It is the volume of flow per unit second, represented as the product of velocity and cross-sectional area.
Q = cross-sectional area(A) * Velocity(V)
Cross-sectional area A of the pipe = π/4 * d² = π/4 * (0.15)² = 0.0176 m².
Velocity V of pipe = [tex]\sqrt{2gh}[/tex] = [tex]\sqrt{2*9.81*2.5}[/tex] = 7.004 m/s.
So, discharge Q = A*V = 0.0176*0.71 = 0.1232 m³/s.
Thus, the volumetric flow rate into the tank if the wine level remains constant will be 0.1232 m³/s.
To get more about volumetric flow rate problems refer to the link,
https://brainly.com/question/26061120
