Answer:
The answer to the question is;
The net force acting on the dam is 73,001,115 N.
Explanation:
To solve he question, we note that
Pressure = Force/Area and the formula for pressure is
Pressure = hρg
While force, F= Pressure × Area
For a small area at the bottom of the dam we have
= hρg×dh×width
Where
w = width of the dam = 125 m
ρ = Density of water = 1.0×10³ m³
g = Acceleration due to gravity = 9.81 m/s²
h = Height of the dam = 11.0 m
Therefore force over the dam wall = [tex]\int\limits^{11}_0 {h\rho gw} \, dh[/tex] = [tex][\frac{h^2}{2} \rho gw]^{11}_0[/tex]
= [ 11²/2×1×10³×9.81×125] - 0
= 73,001,115 N
The net force acting on the dam = 73,001,115 N.
