If a motor driven by PWM using half-bridge operation has a speed of 1,426 rpm at a duty cycle of 100% (full forward), what will its speed be at a duty cycle of 47%

Respuesta :

Answer:

Speed of the motor proportional to duty ratio.

Since duty ratio is proportional to width of the pulse.

So with 61% duty ratio the speed is given by

N = D× Speed of motor with 100% duty ratio

N = 0.47× 1426

= 670.22 rpm

Explanation: