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A puck of mass m 0.085 kg is going in a circle on a horizontal frictionless surface. It is held in its orbit by massless string of length L = 0.84 m. The puck makes one revolution every t= 0.55 s. 50%

What the magnitude of the tension in the string, F, in Newtons, while it spins?

Respuesta :

Answer:

Explanation:

Magnitude of tension

= centripetal force

= m ω²R

= m (2π/T)² R , T is time period of revolution.

= .085 x (2 x 3.14 / .55)² x .84

= 9.3  N .  

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