Answer:
The magnetic field that will allow the electron to go through the region without being deflected is [tex]2\times 10^{-4}\ T[/tex].
Explanation:
Given that,
Velocity of the electron, [tex]v=5\times 10^7\ m/s[/tex]
Electric field, [tex]E=10^4\ V/m\ j[/tex]
We need to find the magnetic field that will allow the electron to go through the region without being deflected. It can be calculated as :
[tex]qE=qvB\ \sin\theta[/tex]
Here, [tex]\sin\theta=90^{\circ}[/tex]
[tex]E=vB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{10^4}{5\times 10^7}\\\\B=2\times 10^{-4}\ T[/tex]
So, the magnetic field that will allow the electron to go through the region without being deflected is [tex]2\times 10^{-4}\ T[/tex].
