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if all resistors are rated 1/4 Watt, what power is being dissipated by the resistive network (the resistive network's effective power rating) at the point one or more elements reach their individual rating

Respuesta :

Answer:

Explanation:

Req = 97 ohms

P1 = P2 = P3 = 1/4 watt

P = I2 × R

R2 is in parallel, Rt

1/Rt = 1/R1 + 1/R2

P = V2/R

At constant voltage, Pt = P1 + P2

R2s in series with R1

Req = Rt + R1

P = I2 × R

At constant current, Peq = Pt + P1

Peq = P1 + P2 + P3

= 3/4 W

= 0.75 W

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