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The US Army's MH-47E Chinook helicopter is used as a heavy lift vehicle. The rotor has three blades that rotate with a frequency f of 225 revolutions per minute. What is the angular velocity ω of the blades, measured in radians per second?

Respuesta :

Answer:

[tex]\omega=23.56\ rad/s[/tex]

Explanation:

Given that, the rotor has three blades that rotate with a frequency f of 225 revolutions per minute. We need to find the angular velocity of the blade in radian per second.

Since, [tex]1\ revolution = 2\pi\ radian[/tex]

So, the angular velocity becomes :

[tex]\omega=\dfrac{2\pi \times 225}{60}[/tex]

[tex]\omega=23.56\ rad/s[/tex]

Hence, this is the required solution.