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Gibson (1986) asked a sample of college students to complete a self-esteem scale on which the midpoint of the scale was the score 108. He found that the average self-esteem score for the samples well above the actual midpoint of the scale. Given that the standard deviation of self esteem scores was 28.15, what would be the score for a sample participant whose ser esteem score was a. 101.67 b. -0.23 c. -0.87 d.0 e. -1.19 f. 0.97

Respuesta :

Answer:

Option B) -0.23                                            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 108

Standard Deviation, σ = 28.15

Formula:

[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]

We are given x  = 101.67

We have to find the corresponding z-score.

Putting values, we get,

[tex]z_{score} = \displaystyle\frac{101.67-108}{28.15} = -0.2248 \approx -0.23[/tex]

Thus, the correct answer is

Option B) -0.23

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