Answer: The molarity and molality of a solution is 1.06 M and 1.11 m respectively.
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
[tex]Molality=\frac{n\times 1000}{W_s}[/tex]
where,
n = moles of solute =
[tex]W_s[/tex] = weight of solvent in g
10.00 g of potassium hydrogen carbonate in 100 g of solution
mass of solvent = mass of solution - mass of solute = (100.0-10.00) = 90.0 g
[tex]Molality=\frac{0.09985\times 1000}{90.0}=1.11m[/tex]
2. Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute = 0.09985
[tex]V_s[/tex] = volume of solution in ml
Density of solution = 1036.5 g/L
Volume of solution =[tex]\frac{\text {mass of solution}}{\text {Density of solution}}=\frac{100.0g}{1.0650g/ml}=93.90ml[/tex]
[tex]Molality= \frac{0.09985\times 1000}{93.90ml}=1.06M[/tex]
