Answer:
[tex]22.08 Ni+14.38 N j[/tex]
Explanation:
We are given that
Force along x- axis =[tex]F_1=11.7i[/tex] N
[tex]F=18.1 N[/tex]
[tex]\theta=55^{\circ}[/tex]
F resolved in two components one is along x- axis and other along y- axis
[tex]F_x=18.1cos55^{\circ}i=10.38 N[/tex]iN
[tex]F_y=18.1sin55^{\circ}j=14.83 j[/tex]N
Total force along x- axis=[tex]F'_x=F_1+F_x=11.7i+10.38i=22.08i N[/tex]
Total force along y- axis=[tex]F_y=14.38 j N[/tex]
Resultant vector =[tex]F'_xi+F_yj=22.08 Ni+14.38 N j[/tex]
