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A fully loaded cart with a mass of 2200 kg starts from the top of a 12-meter hill on a roller coaster.
A. Find the car's gravitational potential energy on the top of the hill?

B. What is the velocity of the car when it reaches the bottom of the hill? Neglect friction

Respuesta :

Answer:

A. potential energy is 258720 Joule

Explanation:

A.Gravitational potential energy is: PE = m × g × h

velocity =  15.33 m/s when the car reaches the bottom of the hill.

where, m = mass

            g = acceleration due to gravity

            h = height from the bottom of hill.

The potential energy is : m×g×h

                                     =(2200×9.8×12)

                                     =258720 Joule

B. at the bottom of the hill, the potential energy is converted into kinetic energy so PE at top = KE at bottom

                    kinetic energy= [tex]\frac{1}{2}[/tex]([tex]m*v^{2}[/tex])

where v = velocity

          m= mass

therefore,               v=[tex]\sqrt\frac{2*K.E}{m} {}[/tex]

                         or,  v=[tex]\sqrt{\frac{2*258720}{2200} }[/tex]

                         or,   v=15.33 m/s

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