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The arm of a crane at a construction site is 17.0 m long, and it makes an angle of 18.7 ◦ with the horizontal. Assume that the maximum load the crane can handle is limited by the amount of torque the load produces around the base of the arm. What maximum torque can the crane withstand if the maximum load the crane can handle is 869 N? Answer in units of N · m

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MechEngineer

Answer:

13993 Nm

Explanation:

Assume the load is vertical, the horizontal moment arm that is perpendicular with the load can be calculated

[tex]s = 17 cos 18.7^0 = 16.1 m[/tex]

Since torque is the product of load and moment arm, with maximum load being 869N the maximum torque that it can handle is

T = Fs = 869 * 16.1 = 13993 Nm

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