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A 0.650 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.900 N to displace the glider to a new equilibrium position, x= 0.070 m. Find the effective spring constant of the system.

Respuesta :

Answer:

Spring constant will be 12.857 N/m

Explanation:

Horizontal force is given  F = 0.900 N

Displaced in position x = 0.070 m

We have to fond the spring constant

Displacing force is equal to [tex]F=Kx[/tex], here K i spring constant

So spring constant [tex]K=\frac{F}{x}=\frac{0.900}{0.070}=12.857N/m[/tex]

So effective spring constant will be 12.85 N /m

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