For this case we must find the solution of the following equation:
[tex]x- \frac {2} {3} = 6 \frac {1} {3}[/tex]
Rewriting the mixed number in the form of improper fraction we have:
[tex]x- \frac {2} {3} = \frac {3 * 6 + 1} {3}\\x- \frac {2} {3} = \frac {19} {3}[/tex]
Add [tex]\frac {2} {3}[/tex] to both sides of the equation:
[tex]x = \frac {19} {3} + \frac {2} {3}[/tex]
We add the fractions with the same denominator:
[tex]x = \frac {19 + 2} {3}\\x = \frac {21} {3}\\x = 7[/tex]
So, the solution is [tex]x = 7[/tex]
Answer:
[tex]x = 7[/tex]
