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A pail of water is rotated in a vertical circle of radius r = 1.6 m . The acceleration of gravity is 9.8 m/s 2 . r v What is the minimum speed of the pail at the top of the circle if no water is to spill out? Answer in units of m/s.

Respuesta :

Answer:3.95 m/s

Explanation:

Given

radius of circle [tex]r=1.6 m[/tex]

Water will not spill if the centripetal acceleration is greater than acceleration due to gravity

i.e. [tex]a_c\geq g[/tex]

[tex]a_c=\frac{v^2}{r}[/tex]

[tex]\frac{v^2}{r}\geq g[/tex]

[tex]v_{min}=\sqrt{gr}[/tex]

[tex]v_{min}=\sqrt{9.8\times 1.6}[/tex]

[tex]v_{min}=\sqrt{15.68}[/tex]

[tex]v_{min}=3.95 m/s[/tex]

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