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A water balloon is dropped from a high building. It falls for 7 seconds before hitting the ground. Determine the velocity it is traveling when it is about to hit the ground, assuming an acceleration due to gravity of − 9.8 m/s 2 and no wind resistance

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Answer:

[tex]v= - 68.6\ m/s[/tex]

Step-by-step explanation:

The velocity of an object moving with a constant acceleration rate is given by:

[tex]v(t) = v_0 +a*t[/tex].

In this case, assume that the initial velocity is zero, acceleration is only due to gravity and that the time of fall just before hitting the ground is 7 seconds:

[tex]v(7) = 0 -9.8*7\\v= - 68.6\ m/s[/tex]

The velocity of the balloon when it is about to hit the ground is -68.6 m/s.

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