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A certain dose of Tums contains 750.0 mg of calcium carbonate, CaCO3, in each tablet. In this problem, you will follow the steps to calculate how many grams of stomach acid, HCl, are neutralized by one tablet of Tums. Balance the chemical equation for the reaction of HCl with CaCO3. chemical equation: HCl + CaCO_{3} -> CaCl_{2} + CO_{2} + H_{2}O HCl+CaCO3⟶CaCl2+CO2+H2O

Using the balanced equation, determine how many moles of HClHCl will react with 1 mol1 mol of CaCO3.CaCO3.

moles of HCl:HCl:

Calculate how many moles 750.0 mg750.0 mg CaCO3CaCO3 is.

750.0 mg CaCO3=750.0 mg CaCO3= _____________Mol CaCO3

Using your answers from the first two questions, calculate how many moles of HClHCl are neutralized when 750.0 mg750.0 mg CaCO3CaCO3 reacts.

moles of HCl:HCl:

Convert the number of moles of HClHCl that you found in the previous question to grams of HCl.HCl. Your answer is the amount (in grams) of HClHCl neutralized by one tablet of Tums.

mass of HClHCl:

Respuesta :

Answer:

0.5475 grams of stomach acid, HCl, are neutralized by one tablet of Tums.

Explanation:

Mass  of calcium carbonate = 750.0 mg = 0.750 g

Moles of calcium carbonate = [tex]\frac{0.750 g}{100 g/mol}=0.0075 mol[/tex]

[tex]2HCl+CaCO_3\rightarrow CaCl_2+CO_2+H_2O[/tex]

According to reaction , 1 mole of calcium carbonate reacts with 2 moles pf HCl.

Then 0.0075 moles of calcium carbonate will recat with:

[tex]\frac{2}{1}\times 0.0075 mol=0.015 mol[/tex] of HCl.

Mass of 0.015 mol of HCl:

0.015 mol × 36.5 g/mol = 0.5475 g

0.5475 grams of stomach acid, HCl, are neutralized by one tablet of Tums.

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