Answer:
A) [tex]\dfrac{11}{23}[/tex]
B) [tex]\dfrac{88}{345}[/tex]
Step-by-step explanation:
A survey of 46 college athletes found that
- 24 played volleyball,
- 22 played basketball.
A) If we pick one athlete survey participant at random, the probability they play basketball is
[tex]P_1=\dfrac{22}{46}=\dfrac{11}{23}[/tex]
B) If we pick 2 athletes at random (without replacement),
- the probability we get one volleyball player is [tex]\dfrac{24}{46}=\dfrac{12}{23};[/tex]
- the probability we get another basketball player is [tex]\dfrac{22}{45}[/tex] (only 45 athletes left).
Thus, the probability we get one volleyball player and one basketball player is
[tex]P_2=\dfrac{12}{23}\cdot \dfrac{22}{45}=\dfrac{88}{345}[/tex]
