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The period of a pendulum is the time it takes for the pendulum to make one full​ back-and-forth swing. The period of a pendulum depends on the length of the pendulum. The formula for the period​ P, in​ seconds, is Upper P equals 2 pi StartRoot StartFraction Upper L Over 32 EndFraction EndRootP=2π L 32​, where L is the length of the pendulum in feet. Find the period of a pendulum whose length is one eightteenth 1 18 ft. Give an exact answer and a​ two-decimal-place approximation.

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Answer: 0.04 s

Explanation:

The given equation for the period [tex]T[/tex] of a pendulum when the acceleration due gravity is given in feet per squared second [tex]g=32 ft/s^{2} [/tex] is:

[tex]T=2 \pi \sqrt{\frac{l}{32 ft/s^{2}}}[/tex]

Where [tex]l=\frac{1}{18} ft[/tex] is the length of the pendulum

[tex]T=2 \pi \sqrt{\frac{\frac{1}{18} ft}{32 ft/s^{2}}}[/tex]

[tex]T=0.04 s[/tex]

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