The width of the new card is 9 inches.
SOLUTION:
Given, we have to solve using equivalent ratios. Wayne has a recipe on a 3-inch-by-5-inch index card that he wants to enlarge to 15 inches long.
We have to find width of the enlargement
Now, dimensions of card is [tex]\bold{\frac{(3 \text { inch })}{(5 \text { inch })}}[/tex]
Let the new width of card be n inches
.
So, New dimensions of card is [tex]\bold{\frac{(n \text { inch })}{(15 \text { inch })}}[/tex]
Then, equivalent ratio is [tex]\bold{\frac{3}{5}=\frac{n}{15}}[/tex]
[tex]\bold{\frac{3}{5}=\frac{n}{15} \rightarrow n=\frac{3}{5} \times 15 \rightarrow n=3 \times 3 \rightarrow n=9}[/tex]
